Varying Electric field intensity and electric field shape

THIS ARTICLE WILL BE MODIFIED ACCORDINGLY

AT PRESENT ITS INCORRECT

AKSHAY DEORAS

Glossary-

*1] Electric charged particle- A particle having an electric charge ( Can be Negative charge or a positive charge)

*2] Acceleration- Rate of change of velocity over a period of time. In one dimension it is rate of changes in speed of a body.

*3] Accelerating electric charged particle- A particle having an electric charge (greater than 0C) which is in acceleration due to action of a certain force

*4] Point charge- A point having a charge. For consideration, the point is taken as a sphere having a well defined diameter

* Point otherwise its a dimension less quantity

*5] Test charge- A ideal charge having magnitude,m (m~ 0)

*6] Electric field- A well defined area around a charge where there is influence of charge

or area around a point charge where force from point charge are active

In this case, area around an electric charge is called electric field

*7] Electric field shape- Shape of the electric field

(FOR THIS ARTICLE, THE SHAPE IS CONSIDERED ON A 2-DIMENSION)

*8] Electric Field Intensity (Electric intensity)-

Is the force experienced by a test charge having certain magnitude ( greater than 0) which is kept in electric field of a point charge

α- direct proportionality symbol

1] VARYING ELECTRIC FIELD INTENSITY FOR A POINT AND TEST CHARGE AT DIFFERENT STATES

Basic-

We consider a point charge P kept in vacuum at rest with a test charge Q at rest

Point charge having magnitude equal to 20C.(Coulomb). Electric field intensity = F/q

i.e

Vector E= Vector F/q

where E and F vector and vectors of electric field and force respectively and q is the charge of P

considering magnitudes-

E=F/q ....................... (1)

F= Ma .........................(2)

where M is mass and a is acceleration of point charge whose force will be experienced by test charge kept in electric field

Putting value of eq.(2) in (1)

E= Ma/q ......................(3)

So Electric field intensity of a test charge at rest in vacuum is given by eq.(3) where

E α Ma

Eα 1/q

Condition-

Now we accelerate the point charge P by providing a Force()

having magnitude equal to 10N and direction along unit vector

()

Let the mass of point charge be 1g and determined acceleration be 10m/s^

Putting values in .. eq(3) and considering vector

= 1*10/20 ()

= 1/2 N/C ()

= 0.5N/C ()..............(4)

IN FIRST CASE WHERE THE POINT CHARGE WAS IN REST we get following result from .... eq(3)

E= Ma/q ......................(3)

Where M=1g

a= 0m/s^

q=20C

= 1*0/20 ()

where () is unit vector along Force vector and accordingly for

=0 () ...................(5)

=0

On comparison of eq (4) and (5) we determine that there is a varying electric field intensity for a stationary point charge and test charge and a accelerating point charge and stationary test charge.

*When the point charge is in a state of motion(increasing magnitude) then electric field intensity on stationary test charge increases in other words as distance between them decreases.

* When point charge is stationary and test charge also then there is no net electric field intensity on a test charge

(II} VARYING ELECTRIC FIELD SHAPE.

TO BE COMPLETED!